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Single Stage Low Pass circuit

Build the Single stage RC circuit shown in Fig. 2, with R=10kOhm, C=0.47μFR=10kOhm, \space C = 0.47\mu F
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Fig. 2: (left) schematic of the single stage RC circuit, (right) implementation on breadboard.

Analysis

The claimed transfer function of this circuit is
T(f)= Vout(f)Vin(f)=11+j2πfRC #(1)\begin{split}\begin{matrix} T(f) = \ \frac{V_{out}(f)}{V_{in}(f)} = \frac{1}{1 + j2\pi fRC}\ \#(1) \\ \end{matrix}\end{split}
Where j=−1 is the imaginary unit.
  1. What is the magnitude of the transfer function?
  1. What is the phase response of the circuit?
  1. What class (low-pass, high-pass, band-pass, band-stop) of filter is this? (This is equivalent to asking what happens to |T(f)| as f gets lower or higher?)
  1. At what frequency does |T(f)|=12≈0.707? (This corresponds to the so-called “half power point” where the ratio of the input to output power is 2 (-3dB) – The circuit drops half of the total power) This value is generally referred to the “cutoff frequency” or “-3dB frequency” and is represented by fcf_c.
  1. (optional) What would happen if I swapped the input and output ports?
    1. (Hint: is there any current flowing through the resistor?)

Measurement

Using the Red Pitaya’s Bode Analyzer tool, measure the frequency response (|T(f)|).
  1. Connect the Red Pitaya to the circuit, also known as the Device Under Test (DUT)), as shown below
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  1. Connect to the Red Pitaya and select the Bode Analyzer tool.
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      A more detailed description of the Bode analyzer can be found here: Bode Analyzer
  1. Click on the settings box to access the sweep settings
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  1. Configure the settings as shown below, we will find new sweep values as we go on, but these should be safe values to try
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  1. Click RUN – The sweep can take awhile to complete.
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  1. To export data: click the Export tab, and either select Graph for a PNG of the chart, or CSV for the raw CSV data of the plot.
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Comparison

Respond to the following questions:
  1. Does the shape of the frequency response match your expectation from the analysis? Is there any point that stands out as odd?
  1. Find the -3dB point in the circuit, and compare this value to the one you previously calculated.